[Smart Math] Algebra Problem 27

Here’s and example of a SMART MATH problem for ALGEBRA.

Algebra

Problem

If the sum of money is divided among ‘n’ children, each child will receive $60. If another child is added to the group and the amount is distributed again each child will receive $50. What is the sum of money to be distributed?

$3
$30
$300
$3000
Cannot be determined

The Usual Method

[contentblock id=google-adsense-post]

Let $‘x’ be the sum of money,

than $60\times n=x$

Also when a child joins, $50\times (n+1)=x$

$\therefore 60n=50(n+1)$

$\therefore 60n=50n+50$

$\therefore 10n=50$

$\therefore n=5$

Hence, $x=60\times n=60\times 5=$ $300

(Ans: 3)

Estimated Time to arrive at the answer = 45 seconds.

Using Technique

[contentblock id=google-adsense-post]

Since $60\times n=x$ and also $50\times (n+1)=x$ ; x should be a multiple of both 50 and 60. Hence simply find the LCM of 60 and 50 which is 300 which is the answer.

(Ans: 3)

Estimated Time to arrive at the answer = 10 seconds.
[starrater tpl=10]

[contentblock id=smartmath-blockquote]

Problem

The Usual Method

Using Technique

One reply on “[Smart Math] Algebra Problem 27”

Leave a Reply Cancel reply