Algebra Smart Math

[Smart Math] Algebra Problem 27

Here’s and example of a SMART MATH problem for ALGEBRA.



If the sum of money is divided among ‘n’ children, each child will receive $60. If another child is added to the group and the amount is distributed again each child will receive $50. What is the sum of money to be distributed?

  1. $3
  2. $30
  3. $300
  4. $3000
  5. Cannot be determined

The Usual Method

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Let $‘x’ be the sum of money,

than 60\times n=x

Also when a child joins, 50\times (n+1)=x

\therefore 60n=50(n+1)

\therefore 60n=50n+50

\therefore 10n=50

\therefore n=5

Hence, x=60\times n=60\times 5= $300

(Ans: 3)

Estimated Time to arrive at the answer = 45 seconds.

Using Technique

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Since 60\times n=x and also 50\times (n+1)=x; x should be a multiple of both 50 and 60. Hence simply find the LCM of 60 and 50 which is 300 which is the answer.

(Ans: 3)

Estimated Time to arrive at the answer = 10 seconds.
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One reply on “[Smart Math] Algebra Problem 27”

That’s smart. It should be clicking in the minds of the people preparing for competitive exams in no time at all. Because it’s logical. Plain, simple, but smart.

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