Here’s and example of a **SMART MATH** problem for **ALGEBRA.**

**Problem**

**Problem**

A sum of $45 is made of 100 coins, partly of 50 cents and 25 cents. What is the number of 50 cents coins?

- 20
- 40
- 50
- 75
- 80

**The Usual Method**

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Let the number of 50 cents coins be ‘x’, so the number of 25 cents coins will be (100 – x).

Thus,

(Ans: 5)

Estimated Time to arrive at the answer = 45 seconds.

**Using Technique**

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Use the alligation technique here. The average value of coin = or 45 cents

Thus,

Thus for every one 25 cents coins, there are four 50 cents coins. Dividing 100 coins in this ratio, we get 80 coins of 50 cents.

(Ans: 5)

Estimated Time to arrive at the answer = 15 seconds.

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