Here’s and example of a **SMART MATH** problem for **ARITHMETIC.**

**Problem**

**Problem**

Simplify

**The Usual Method**

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Simplifying the numerator of the equation, we get:

=

and,

=

Hence numerator is

Similarly, simplifying the denominator, we get:

=

Thus the equation now becomes:

This can be written as:

=

=

=

**(Ans: 5)**

*Estimated Time to arrive at the answer = 150 seconds.*

**Using Technique**

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Simply observe that since all the terms in the numerator are positive, simplifying the numerator will also give all positive terms.

The denominator has a negative sign. However, the process of rationalization would require its conjugate to be multiplied to result in a rational number in the denominator. This conjugate multiplier will have positive terms. Hence, when it multiplies with the all positive term numerator, we will get a product in the numerator with all positive terms. The only option that has all positive terms in the numerator is option ‘5’.

**(Ans: 5)**

*Estimated Time to arrive at the answer = 15 seconds.*

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