Here’s and example of a **SMART MATH** problem for **RATIO PROPORTION.**

**Problem**

**Problem**

What is A’s share of an amount of $7000, if he gets of what B and of what C gets?

- 700
- 900
- 1000
- 1100
- 1200

**The Usual Method**

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Let the share of A be ‘*x*’

Hence, B’s share = 2*x* and C’s share = 4*x*.

Hence total amount shared =

**(Ans: 3)**

*Estimated Time to arrive at the answer = 45 seconds.*

**Using Technique**

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Assuming option ‘1’ to be the answer,

A’s share = 700

B’s share = 1400 and

C’s share = 2800

But, 700 + 1400 + 2800 7000 and hence options ‘1’ is not the answer.

Assuming option ‘2’ to be the answer,

A’s share = 900

B’s share = 1800 and

C’s share = 3600

But, 900 + 1800 + 3600 7000 and hence options ‘2’ is not the answer.

Assuming option ‘3’ to be the answer,

A’s share = 1000

B’s share = 2000 and

C’s share = 4000

But, 1000 + 2000 + 4000 = 7000 and hence options ‘3’ is the answer.

No need to check further as there can be only one single answer.

**(Ans: 3)**

*Estimated Time to arrive at the answer = 30 seconds, but much easier.*

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