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# [Smart Math] Ratio Proportion Problem 49

Here’s and example of a SMART MATH problem for RATIO PROPORTION.

### Problem

A, B and C are mixed together and their volumes are in the ratio 4 : 5 : 6 respectively. If the weights of equal volumes of A, B and C are in the ratio 2 : 3 : 4, what is the weight of the heaviest substance, if the weight of the mixture is 1123.84 lbs.

1. 573.88 lbs
2. 673.88 lbs
3. 473.88 lbs
4. 773.88 lbs
5. cannot be determined

### The Usual Method

The ratio of weights of A, B and C in the mixture is $4\times 2:5\times 3:6\times 4$ = 8 : 15 : 24.

From this it is obvious that C will have the most weight. Hence the quantity of C in the mixture is: $\frac{24}{8+15+24}\times 1123.84$

$=\frac{24}{47}\times 1123.84=$ 573.88 lbs

(Ans: 1)

Estimated Time to arrive at the answer = 60 seconds.

### Using Technique

First get the ratio of weights of A, B and C in the mixture i.e. 8 : 15 : 24 ( $4\times 2:5\times 3:6\times 4$)