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# [Smart Math] Time Speed Distance Problem 10

Here’s and example of a SMART MATH problem for TIME SPEED DISTANCE.

### Problem

In a kilometer race B can give C a 100 meters and A 150 meters start. How many meters start can C give A?

1. 50
2. 49
3. 500/9
4. 8500/9
5. 50/9

### The Usual Method

When B gives C a 100 meters start in kilometer race, B travels 1000 meters and C 900 meters. Also when B travels 1000 meters, A will travel 850 meters. Thus we can write as follows:

A                     B                     C

850                  1000                900

Thus when C travels 1000 meters, A will travel ‘x’ meters.

A                     C

x 1000

$\therefore x=\frac{850\times 1000}{900}=\frac{8500}{9}$

Hence C can give A an start of 1000 – $\frac{8500}{9}$ = $\frac{500}{9}$meters

(Ans: 3)

Estimated Time to arrive at the answer = 45 seconds.