Here’s and example of a **SMART MATH** problem for **TIME SPEED DISTANCE.**

**Problem**

**Problem**

If I walk at 3 mph (miles per hour), I miss the train by 2 minutes. If however, I walk at 4 mph, I reach the station 2 minutes before arrival of the train. How far do I walk to reach the station?

- mile
- mile
- 1 mile
- miles
- miles

**The Usual Method**

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Let the distance between home and station be ‘4’ miles. Hence, time taken to cover *d* miles at 3 mph, hours.

Similarly, time taken at 4 mph, hours

minutes

Hence, hours

mile

**(Ans: 2)**

*Estimated Time to arrive at the answer = 45 seconds.*

**Using Technique**

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To cover 1 mile @ 3 mph, it takes 20 minutes

To cover 1 mile @ 4 mph, it takes 15 minutes

Hence, time gap = 20 – 15 = 5 minutes

Thus for a distance of 1 mile, time gap = 5 minutes

Hence, a time gap of 4 minutes (2 + 2), distance is correspondingly mile.

**(Ans: 2)**

*Estimated Time to arrive at the answer = 10 seconds.*

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