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# [Smart Math] Time Speed Distance Problem 8

Here’s and example of a SMART MATH problem for TIME SPEED DISTANCE. ### Problem

In a 200 meters race, A beats B by 20 meters, while in a 100 meters race B beats C by 5 meters. By how many meters will A beat C in a kilometer race assuming that speeds of A, B and C do not change in the races?

1. 150
2. 145
3. 130
4. 125
5. 110

### The Usual Method

If in a 200 meters race A beats B by 20 meters, than in a kilometer race (1000 meters), A will beat B by 100 meters.

Similarly if in a 100 meters race B beats C by 5 meters, in a kilometer race, B will beat C by 50 meters.

Hence,

A                     B                     C

1000                900

aaaaaaaaaa 1000                950

i.e.                   A                    B                     C

aaaaaa 1000 x 1000    900 x 1000      900 x 950

i.e                    1000                900                  855

Hence, in a kilometer race if A runs 1000 meters, B runs 900 and C runs 855 meters. Hence, A beats C by 1000 – 855 = 145 meters.

(Ans: 2)

Estimated Time to arrive at the answer = 60 seconds.